MATLAB:Iterative Structures

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Often in solving engineering problems you will want a program to run pieces of code several times with slightly - or possibly vastly - different parameters. The number of times to run the code may depend on some logical expression or on the number of columns in a particular matrix. For these, you will use iterative structures.

Indexing Items

While using a loop, you may want to access certain elements of matrices and vectors within that loop. To do this, you will need a variable that holds on to the index number you want to access. There are two fundamentally different ways to create this variable: using the loop scanning variable itself as in index it appropriate, or creating an external counter.

Scanner Variable

If you have a loop that is meant to go through a pre-determined number of iterations, and you have set up a loop counter to count the iteration you are on:

for K=1:12
    % Code
end

you can use the scanning variable as the indexing variable. For instance, to obtain twelve different values from a user, you can use the following code:

Temperatures = [];
for K=1:12
    Temperatures(K) = input('Enter a temperature: ');
end

and the fact that K takes on the values of 1, 2, 3, etc., will work as your index variable. The Temperatures variable will end up as a 1 x 12 matrix with the values the users gave you.

External Variable

Sometimes, you will not have an integer-based scanning variable - or you may not have a scanning variable at all (example: while loops). For those, you may have to start an external counter. For example, if you want to store temperature inputs so long as the temperatures entered are non-negative, you could write:

NumTemps = 0;
Temperatures = [];
TempInput = 0; % or any non-negative value here
while TempInput>=0
    TempInput = input('Enter a temperature (negative to stop): ');
    if TempInput>=0
        NumTemps = NumTemps + 1;
        Temperatures(NumTemps) = TempInput;
    end
end

Note that the if statement is used to keep from including the final negative temperature as a part of the matrix. At the end of this code, NumTemps will be a value that indicates how many entries there are in Temperatures, and Temperatures will be a 1 x NumTemps matrix of temperature values.


Initializing Large Vectors

One of the dangers in MATLAB's ability to automatically resize a vector is the amount of time it actually takes to do that.

Iterative Resizing

Consider the following:

clear
tic
y0 = 0;
v0 = 5;
a  = -9.81;
NP = 10;
t = linspace(0, 5, NP)
for k=1:NP
   y(k) = y0 + v0*t(k) + 0.5*a*t(k).^2;
end
toc

This code takes, on average, 36 microseconds to run. If NP is increased to 100, the average time to complete goes up to about 150 microseconds. NP of 1000 increases the time to 2.25 ms. And NP of 100000 increases the time to over 10 s! The graph below shows, on a log scale, time to complete as a function of NP:

NoInitPlot.png

Clearly, this becomes a major problem as the number of points increases.

Initialized

Remarkably, adding a single line completely changes the timing of the program. The following program:

clear
tic
y0 = 0;
v0 = 5;
a  = -9.81;
NP = 10;
t = linspace(0, 5, NP)
y = t*0;     % here's the only thing that changed!!!
for k=1:NP
   y(k) = y0 + v0*t(k) + 0.5*a*t(k).^2;
end
toc

generates the following time vs. NP graph:

InitPlot.png

which indicates a reduction, by three orders of magnitude, of the run time. And all that was done was creating a vector y of the appropriate size before running the loop, rather than continuously changing the vector size inside the loop.

Vectorized

Of course, the fastest version of the code uses MATLAB's ability to vectorize:

clear
tic
y0 = 0;
v0 = 5;
a  = -9.81;
NP = 10;
t = linspace(0, 5, NP)
y = y0 + v0*t + 0.5*a*t.^2;
toc

which generates the following time vs. NP graph:

NoLoopPlot.png

Questions

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External Links

References